Problem
Given an integer array nums
and an integer k
, return true
**if there are two *distinct indices* i
and j
in the array such that nums[i] == nums[j]
and **abs(i - j) <= k
.
Example 1:
Input: nums = [1,2,3,1], k = 3
Output: true
Example 2:
Input: nums = [1,0,1,1], k = 1
Output: true
Example 3:
Input: nums = [1,2,3,1,2,3], k = 2
Output: false
Constraints:
1 <= nums.length <= 105
-109 <= nums[i] <= 109
0 <= k <= 105
Solution
/**
* @param {number[]} nums
* @param {number} k
* @return {boolean}
*/
var containsNearbyDuplicate = function(nums, k) {
var map = {};
for (var i = 0; i < nums.length; i++) {
if (map[nums[i]] !== undefined && i - map[nums[i]] <= k) return true;
map[nums[i]] = i;
}
return false;
};
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).