Problem
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Example:
Given the sorted linked list: [-10,-3,0,5,9],
One possible answer is: [0,-3,9,-10,null,5], which represents the following height balanced BST:
0
/ \
-3 9
/ /
-10 5
Solution
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {ListNode} head
* @return {TreeNode}
*/
var sortedListToBST = function(head) {
return helper(head, null);
};
var helper = function (head, foot) {
var fast = head;
var slow = head;
var node = null;
if (head === foot) return null;
while (fast !== foot && fast.next !== foot) {
fast = fast.next.next;
slow = slow.next;
}
node = new TreeNode(slow.val);
node.left = helper(head, slow);
node.right = helper(slow.next, foot);
return node;
};
Explain:
nope.
Complexity:
- Time complexity : O(log(n)).
- Space complexity : O(n).