Problem
Given a string s
, find the first non-repeating character in it and return its index. If it does not exist, return -1
.
Example 1:
Input: s = "leetcode"
Output: 0
Example 2:
Input: s = "loveleetcode"
Output: 2
Example 3:
Input: s = "aabb"
Output: -1
Constraints:
1 <= s.length <= 105
s
consists of only lowercase English letters.
Solution
/**
* @param {string} s
* @return {number}
*/
var firstUniqChar = function(s) {
var map = {};
for (var i = 0; i < s.length; i++) {
map[s[i]] = (map[s[i]] || 0) + 1;
}
for (var i = 0; i < s.length; i++) {
if (map[s[i]] === 1) return i;
}
return -1;
};
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(1).