785. Is Graph Bipartite?

Difficulty:
Related Topics:
Similar Questions:

Problem

There is an undirected graph with n nodes, where each node is numbered between 0 and n - 1. You are given a 2D array graph, where graph[u] is an array of nodes that node u is adjacent to. More formally, for each v in graph[u], there is an undirected edge between node u and node v. The graph has the following properties:

A graph is bipartite if the nodes can be partitioned into two independent sets A and B such that every edge in the graph connects a node in set A and a node in set B.

Return true** if and only if it is bipartite**.

  Example 1:

Input: graph = [[1,2,3],[0,2],[0,1,3],[0,2]]
Output: false
Explanation: There is no way to partition the nodes into two independent sets such that every edge connects a node in one and a node in the other.

Example 2:

Input: graph = [[1,3],[0,2],[1,3],[0,2]]
Output: true
Explanation: We can partition the nodes into two sets: {0, 2} and {1, 3}.

  Constraints:

Solution

/**
 * @param {number[][]} graph
 * @return {boolean}
 */
var isBipartite = function(graph) {
    var map = {};
    for (var i = 0; i < graph.length; i++) {
        if (!dfs(graph, map, i)) return false;
    }
    return true;
};

var dfs = function(graph, map, i, group) {
    if (map[i]) return !group || group === map[i];
    map[i] = group || 1;
    for (var j = 0; j < graph[i].length; j++) {
        if (!dfs(graph, map, graph[i][j], map[i] === 1 ? 2 : 1)) return false;
    }
    return true;
};

Explain:

DFS with memorize.

Complexity: