Problem
Given a string s
and an integer k
, return **the maximum number of vowel letters in any substring of *s
* with length **k
.
Vowel letters in English are 'a'
, 'e'
, 'i'
, 'o'
, and 'u'
.
Example 1:
Input: s = "abciiidef", k = 3
Output: 3
Explanation: The substring "iii" contains 3 vowel letters.
Example 2:
Input: s = "aeiou", k = 2
Output: 2
Explanation: Any substring of length 2 contains 2 vowels.
Example 3:
Input: s = "leetcode", k = 3
Output: 2
Explanation: "lee", "eet" and "ode" contain 2 vowels.
Constraints:
1 <= s.length <= 105
s
consists of lowercase English letters.1 <= k <= s.length
Solution
/**
* @param {string} s
* @param {number} k
* @return {number}
*/
var maxVowels = function(s, k) {
var i = 0;
var j = 0;
var count = isVowel(s, j) ? 1 : 0;
var max = count;
while (j < s.length - 1) {
j++;
count += (isVowel(s, j) ? 1 : 0);
if (j - i > k - 1) {
count -= (isVowel(s, i) ? 1 : 0);
i++;
}
max = Math.max(max, count);
}
return max;
};
var isVowel = function(s, i) {
return ['a', 'e', 'i', 'o', 'u'].includes(s[i]);
};
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(1).