Problem
Given an array of integers nums
, return **the number of *good pairs***.
A pair (i, j)
is called good if nums[i] == nums[j]
and i
< j
.
Example 1:
Input: nums = [1,2,3,1,1,3]
Output: 4
Explanation: There are 4 good pairs (0,3), (0,4), (3,4), (2,5) 0-indexed.
Example 2:
Input: nums = [1,1,1,1]
Output: 6
Explanation: Each pair in the array are good.
Example 3:
Input: nums = [1,2,3]
Output: 0
Constraints:
1 <= nums.length <= 100
1 <= nums[i] <= 100
Solution
/**
* @param {number[]} nums
* @return {number}
*/
var numIdenticalPairs = function(nums) {
var map = Array(100).fill(0);
for (var i = 0; i < nums.length; i++) {
map[nums[i] - 1]++;
}
var res = 0;
for (var j = 0; j < map.length; j++) {
res += helper(map[j] - 1);
}
return res;
};
var helper = function(num) {
return num * (1 + num) / 2;
};
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(n).