Problem
Given a linked list, swap every two adjacent nodes and return its head.
Example:
Given 1->2->3->4, you should return the list as 2->1->4->3.
Note:
- Your algorithm should use only constant extra space.
- You may not modify the values in the list's nodes, only nodes itself may be changed.
Solution
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} head
* @return {ListNode}
*/
var swapPairs = function(head) {
var out = new ListNode(0);
var now = out;
out.next = head;
while (now.next && now.next.next) {
now = swap(now, now.next, now.next.next);
}
return out.next;
};
var swap = function (a, b, c) {
a.next = c;
b.next = c.next;
c.next = b;
return b;
};
Explain:
nope.
Complexity:
- Time complexity : O(n).
- Space complexity : O(1).